11t^2+t+100=67

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Solution for 11t^2+t+100=67 equation: 



11t^2+t+100=67

We move all terms to the left:

11t^2+t+100-(67)=0

We add all the numbers together, and all the variables

11t^2+t+33=0

a = 11; b = 1; c = +33;
Δ = b2-4ac
Δ = 12-4·11·33
Δ = -1451
Delta is less than zero, so there is no solution for the equation

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